98-x-24x^2=0

Solution for 98-x-24x^2=0 equation:

98-x-24x^2=0

We add all the numbers together, and all the variables

-24x^2-1x+98=0

a = -24; b = -1; c = +98;
Δ = b2-4ac
Δ = -12-4·(-24)·98
Δ = 9409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9409}=97$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-97}{2*-24}=\frac{-96}{-48}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+97}{2*-24}=\frac{98}{-48}
=-2+1/24
$